122=2-5(4k-8)

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Solution for 122=2-5(4k-8) equation: 



122=2-5(4k-8)

We move all terms to the left:

122-(2-5(4k-8))=0



We calculate terms in parentheses: -(2-5(4k-8)), so:

2-5(4k-8)

determiningTheFunctionDomain
-5(4k-8)+2

We multiply parentheses

-20k+40+2

We add all the numbers together, and all the variables

-20k+42

Back to the equation:

-(-20k+42)



We get rid of parentheses

20k-42+122=0

We add all the numbers together, and all the variables

20k+80=0

We move all terms containing k to the left, all other terms to the right

20k=-80

k=-80/20

k=-4

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