122+(22x-3)=(8x+20)

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Solution for 122+(22x-3)=(8x+20) equation: 



122+(22x-3)=(8x+20)

We move all terms to the left:

122+(22x-3)-((8x+20))=0

We get rid of parentheses

22x-((8x+20))-3+122=0



We calculate terms in parentheses: -((8x+20)), so:

(8x+20)

We get rid of parentheses

8x+20

Back to the equation:

-(8x+20)



We add all the numbers together, and all the variables

22x-(8x+20)+119=0

We get rid of parentheses

22x-8x-20+119=0

We add all the numbers together, and all the variables

14x+99=0

We move all terms containing x to the left, all other terms to the right

14x=-99

x=-99/14

x=-7+1/14

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