121q2-100=0

Solution for 121q2-100=0 equation:

121q^2-100=0

a = 121; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·121·(-100)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-220}{2*121}=\frac{-220}{242}
=-10/11
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+220}{2*121}=\frac{220}{242}
=10/11
$