120=w(w+2)

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Solution for 120=w(w+2) equation:


Simplifying
120 = w(w + 2)

Reorder the terms:
120 = w(2 + w)
120 = (2 * w + w * w)
120 = (2w + w2)

Solving
120 = 2w + w2

Solving for variable 'w'.

Reorder the terms:
120 + -2w + -1w2 = 2w + -2w + w2 + -1w2

Combine like terms: 2w + -2w = 0
120 + -2w + -1w2 = 0 + w2 + -1w2
120 + -2w + -1w2 = w2 + -1w2

Combine like terms: w2 + -1w2 = 0
120 + -2w + -1w2 = 0

Factor a trinomial.
(10 + -1w)(12 + w) = 0

Subproblem 1

Set the factor '(10 + -1w)' equal to zero and attempt to solve: Simplifying 10 + -1w = 0 Solving 10 + -1w = 0 Move all terms containing w to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1w = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1w = 0 + -10 -1w = 0 + -10 Combine like terms: 0 + -10 = -10 -1w = -10 Divide each side by '-1'. w = 10 Simplifying w = 10

Subproblem 2

Set the factor '(12 + w)' equal to zero and attempt to solve: Simplifying 12 + w = 0 Solving 12 + w = 0 Move all terms containing w to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + w = 0 + -12 Combine like terms: 12 + -12 = 0 0 + w = 0 + -12 w = 0 + -12 Combine like terms: 0 + -12 = -12 w = -12 Simplifying w = -12

Solution

w = {10, -12}

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