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120=23x-x2
We move all terms to the left:
120-(23x-x2)=0
We add all the numbers together, and all the variables
-(+23x-1x^2)+120=0
We get rid of parentheses
1x^2-23x+120=0
We add all the numbers together, and all the variables
x^2-23x+120=0
a = 1; b = -23; c = +120;
Δ = b2-4ac
Δ = -232-4·1·120
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-7}{2*1}=\frac{16}{2} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+7}{2*1}=\frac{30}{2} =15 $
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