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120=1-10(x-3)
We move all terms to the left:
120-(1-10(x-3))=0
We calculate terms in parentheses: -(1-10(x-3)), so:We get rid of parentheses
1-10(x-3)
determiningTheFunctionDomain -10(x-3)+1
We multiply parentheses
-10x+30+1
We add all the numbers together, and all the variables
-10x+31
Back to the equation:
-(-10x+31)
10x-31+120=0
We add all the numbers together, and all the variables
10x+89=0
We move all terms containing x to the left, all other terms to the right
10x=-89
x=-89/10
x=-8+9/10
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