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1200-1/5x=8x
We move all terms to the left:
1200-1/5x-(8x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-8x-1/5x+1200=0
We multiply all the terms by the denominator
-8x*5x+1200*5x-1=0
Wy multiply elements
-40x^2+6000x-1=0
a = -40; b = 6000; c = -1;
Δ = b2-4ac
Δ = 60002-4·(-40)·(-1)
Δ = 35999840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{35999840}=\sqrt{16*2249990}=\sqrt{16}*\sqrt{2249990}=4\sqrt{2249990}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6000)-4\sqrt{2249990}}{2*-40}=\frac{-6000-4\sqrt{2249990}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6000)+4\sqrt{2249990}}{2*-40}=\frac{-6000+4\sqrt{2249990}}{-80} $
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