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12/q=2q+2
We move all terms to the left:
12/q-(2q+2)=0
Domain of the equation: q!=0We get rid of parentheses
q∈R
12/q-2q-2=0
We multiply all the terms by the denominator
-2q*q-2*q+12=0
We add all the numbers together, and all the variables
-2q-2q*q+12=0
Wy multiply elements
-2q^2-2q+12=0
a = -2; b = -2; c = +12;
Δ = b2-4ac
Δ = -22-4·(-2)·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-2}=\frac{-8}{-4} =+2 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-2}=\frac{12}{-4} =-3 $
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