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12/5k=3
We move all terms to the left:
12/5k-(3)=0
Domain of the equation: 5k!=0We multiply all the terms by the denominator
k!=0/5
k!=0
k∈R
-3*5k+12=0
Wy multiply elements
-15k+12=0
We move all terms containing k to the left, all other terms to the right
-15k=-12
k=-12/-15
k=4/5
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