12/5=(3+r)/r

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Solution for 12/5=(3+r)/r equation: 



12/5=(3+r)/r

We move all terms to the left:

12/5-((3+r)/r)=0



Domain of the equation: r)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

-((r+3)/r)+12/5=0

We calculate fractions


(-((r+3)*5)/r*5)+12r/r*5)=0



We calculate terms in parentheses: +(-((r+3)*5)/r*5), so:

-((r+3)*5)/r*5

We multiply all the terms by the denominator


-((r+3)*5)



We calculate terms in parentheses: -((r+3)*5), so:

(r+3)*5

We multiply parentheses

5r+15

Back to the equation:

-(5r+15)



We get rid of parentheses

-5r-15

Back to the equation:

+(-5r-15)



We get rid of parentheses

-5r+12r/r*5)-15=0

We multiply all the terms by the denominator


-5r*r*5)-15+12r=0

Wy multiply elements

-25r^3*5=0

We do not support erpression: r^3

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