12/3b=2

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Solution for 12/3b=2 equation: 



12/3b=2

We move all terms to the left:

12/3b-(2)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We multiply all the terms by the denominator


-2*3b+12=0

Wy multiply elements

-6b+12=0

We move all terms containing b to the left, all other terms to the right

-6b=-12

b=-12/-6

b=+2

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