12/36x+12/24=12/76x

Solution for 12/36x+12/24=12/76x equation:

12/36x+12/24=12/76x

We move all terms to the left:

12/36x+12/24-(12/76x)=0


Domain of the equation: 36x!=0

x!=0/36

x!=0

x∈R



Domain of the equation: 76x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

12/36x-(+12/76x)+12/24=0

We get rid of parentheses

12/36x-12/76x+12/24=0

We calculate fractions


229824x^2/131328x^2+43776x/131328x^2+(-20736x)/131328x^2=0

We multiply all the terms by the denominator


229824x^2+43776x+(-20736x)=0

We get rid of parentheses

229824x^2+43776x-20736x=0

We add all the numbers together, and all the variables

229824x^2+23040x=0

a = 229824; b = 23040; c = 0;
Δ = b2-4ac
Δ = 230402-4·229824·0
Δ = 530841600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{530841600}=23040$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23040)-23040}{2*229824}=\frac{-46080}{459648}
=-40/399
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23040)+23040}{2*229824}=\frac{0}{459648}
=0
$