12/2x+27/3x=5

Solution for 12/2x+27/3x=5 equation:

12/2x+27/3x=5

We move all terms to the left:

12/2x+27/3x-(5)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


36x/6x^2+54x/6x^2-5=0

We multiply all the terms by the denominator


36x+54x-5*6x^2=0

We add all the numbers together, and all the variables

90x-5*6x^2=0

Wy multiply elements

-30x^2+90x=0

a = -30; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·(-30)·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*-30}=\frac{-180}{-60}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*-30}=\frac{0}{-60}
=0
$