12/2-x-13/x-5=0

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Solution for 12/2-x-13/x-5=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

12/2-x-(13/x)-5 = 0

12/2-x-13*x^-1-5 = 0

1*x^0-1*x^1-13*x^-1 = 0

(1*x^1-1*x^2-13*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^1-1*x^2-13*x^0) = 0

x^1

x-x^2-13 = 0

x-x^2-13 = 0

DELTA = 1^2-(-13*(-1)*4)

DELTA = -51

DELTA < 0

x in { } 

x belongs to the empty set

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