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12/(x+2)=10/5
We move all terms to the left:
12/(x+2)-(10/5)=0
Domain of the equation: (x+2)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
12/(x+2)-2=0
We multiply all the terms by the denominator
-2*(x+2)+12=0
We multiply parentheses
-2x-4+12=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4
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