12/(x+1)=132/35

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Solution for 12/(x+1)=132/35 equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

12/(x+1) = 132/35 // - 132/35

12/(x+1)-(132/35) = 0

12/(x+1)-132/35 = 0

(12*35)/(35*(x+1))+(-132*(x+1))/(35*(x+1)) = 0

12*35-132*(x+1) = 0

288-132*x = 0

(288-132*x)/(35*(x+1)) = 0

(288-132*x)/(35*(x+1)) = 0 // * 35*(x+1)

288-132*x = 0

288-132*x = 0 // - 288

-132*x = -288 // : -132

x = -288/(-132)

x = 24/11

x = 24/11

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