12/(k-6)=3/11

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Solution for 12/(k-6)=3/11 equation: 


D( k )

k-6 = 0

k-6 = 0

k-6 = 0

k-6 = 0 // + 6

k = 6

k in (-oo:6) U (6:+oo)

12/(k-6) = 3/11 // - 3/11

12/(k-6)-(3/11) = 0

12/(k-6)-3/11 = 0

(11*12)/(11*(k-6))+(-3*(k-6))/(11*(k-6)) = 0

11*12-3*(k-6) = 0

150-3*k = 0

(150-3*k)/(11*(k-6)) = 0

(150-3*k)/(11*(k-6)) = 0 // * 11*(k-6)

150-3*k = 0

150-3*k = 0 // - 150

-3*k = -150 // : -3

k = -150/(-3)

k = 50

k = 50

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