12/(a+1)=132/35

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Solution for 12/(a+1)=132/35 equation: 


D( a )

a+1 = 0

a+1 = 0

a+1 = 0

a+1 = 0 // - 1

a = -1

a in (-oo:-1) U (-1:+oo)

12/(a+1) = 132/35 // - 132/35

12/(a+1)-(132/35) = 0

12/(a+1)-132/35 = 0

(12*35)/(35*(a+1))+(-132*(a+1))/(35*(a+1)) = 0

12*35-132*(a+1) = 0

288-132*a = 0

(288-132*a)/(35*(a+1)) = 0

(288-132*a)/(35*(a+1)) = 0 // * 35*(a+1)

288-132*a = 0

288-132*a = 0 // - 288

-132*a = -288 // : -132

a = -288/(-132)

a = 24/11

a = 24/11

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