12/(19x-3)=3/5x

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Solution for 12/(19x-3)=3/5x equation: 



12/(19x-3)=3/5x

We move all terms to the left:

12/(19x-3)-(3/5x)=0



Domain of the equation: (19x-3)!=0

We move all terms containing x to the left, all other terms to the right

19x!=3

x!=3/19

x!=3/19

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

12/(19x-3)-(+3/5x)=0

We get rid of parentheses

12/(19x-3)-3/5x=0

We calculate fractions


60x/(95x^2-15x)+(-57x+9)/(95x^2-15x)=0

We multiply all the terms by the denominator


60x+(-57x+9)=0

We get rid of parentheses

60x-57x+9=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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