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12-7a(2)+5a=12-9a
We move all terms to the left:
12-7a(2)+5a-(12-9a)=0
We add all the numbers together, and all the variables
-7a2+5a-(-9a+12)+12=0
We add all the numbers together, and all the variables
-7a^2+5a-(-9a+12)+12=0
We get rid of parentheses
-7a^2+5a+9a-12+12=0
We add all the numbers together, and all the variables
-7a^2+14a=0
a = -7; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-7)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-7}=\frac{-28}{-14} =+2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-7}=\frac{0}{-14} =0 $
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