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12-6x=2(5x^2)
We move all terms to the left:
12-6x-(2(5x^2))=0
determiningTheFunctionDomain -6x-25x^2+12=0
We add all the numbers together, and all the variables
-25x^2-6x+12=0
a = -25; b = -6; c = +12;
Δ = b2-4ac
Δ = -62-4·(-25)·12
Δ = 1236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1236}=\sqrt{4*309}=\sqrt{4}*\sqrt{309}=2\sqrt{309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{309}}{2*-25}=\frac{6-2\sqrt{309}}{-50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{309}}{2*-25}=\frac{6+2\sqrt{309}}{-50} $
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