12-5z=12-2(6z+7)

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Solution for 12-5z=12-2(6z+7) equation: 



12-5z=12-2(6z+7)

We move all terms to the left:

12-5z-(12-2(6z+7))=0



We calculate terms in parentheses: -(12-2(6z+7)), so:

12-2(6z+7)

determiningTheFunctionDomain
-2(6z+7)+12

We multiply parentheses

-12z-14+12

We add all the numbers together, and all the variables

-12z-2

Back to the equation:

-(-12z-2)



We get rid of parentheses

-5z+12z+2+12=0

We add all the numbers together, and all the variables

7z+14=0

We move all terms containing z to the left, all other terms to the right

7z=-14

z=-14/7

z=-2

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