12-4(4-x)+6x=2(2x-5)

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Solution for 12-4(4-x)+6x=2(2x-5) equation:



12-4(4-x)+6x=2(2x-5)
We move all terms to the left:
12-4(4-x)+6x-(2(2x-5))=0
We add all the numbers together, and all the variables
-4(-1x+4)+6x-(2(2x-5))+12=0
We add all the numbers together, and all the variables
6x-4(-1x+4)-(2(2x-5))+12=0
We multiply parentheses
6x+4x-(2(2x-5))-16+12=0
We calculate terms in parentheses: -(2(2x-5)), so:
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
We add all the numbers together, and all the variables
10x-(4x-10)-4=0
We get rid of parentheses
10x-4x+10-4=0
We add all the numbers together, and all the variables
6x+6=0
We move all terms containing x to the left, all other terms to the right
6x=-6
x=-6/6
x=-1

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