12-4(3x-5)=7(10-x)

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Solution for 12-4(3x-5)=7(10-x) equation: 



12-4(3x-5)=7(10-x)

We move all terms to the left:

12-4(3x-5)-(7(10-x))=0

We add all the numbers together, and all the variables

-4(3x-5)-(7(-1x+10))+12=0

We multiply parentheses

-12x-(7(-1x+10))+20+12=0



We calculate terms in parentheses: -(7(-1x+10)), so:

7(-1x+10)

We multiply parentheses

-7x+70

Back to the equation:

-(-7x+70)



We add all the numbers together, and all the variables

-12x-(-7x+70)+32=0

We get rid of parentheses

-12x+7x-70+32=0

We add all the numbers together, and all the variables

-5x-38=0

We move all terms containing x to the left, all other terms to the right

-5x=38

x=38/-5

x=-7+3/5

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