12-3r+6(r-3)=15

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Solution for 12-3r+6(r-3)=15 equation: 



12-3r+6(r-3)=15

We move all terms to the left:

12-3r+6(r-3)-(15)=0

We add all the numbers together, and all the variables

-3r+6(r-3)-3=0

We multiply parentheses

-3r+6r-18-3=0

We add all the numbers together, and all the variables

3r-21=0

We move all terms containing r to the left, all other terms to the right

3r=21

r=21/3

r=7

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