12-3(y-2)=3+5(y-2)

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Solution for 12-3(y-2)=3+5(y-2) equation: 



12-3(y-2)=3+5(y-2)

We move all terms to the left:

12-3(y-2)-(3+5(y-2))=0

We multiply parentheses

-3y-(3+5(y-2))+6+12=0



We calculate terms in parentheses: -(3+5(y-2)), so:

3+5(y-2)

determiningTheFunctionDomain
5(y-2)+3

We multiply parentheses

5y-10+3

We add all the numbers together, and all the variables

5y-7

Back to the equation:

-(5y-7)



We add all the numbers together, and all the variables

-3y-(5y-7)+18=0

We get rid of parentheses

-3y-5y+7+18=0

We add all the numbers together, and all the variables

-8y+25=0

We move all terms containing y to the left, all other terms to the right

-8y=-25

y=-25/-8

y=3+1/8

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