12-3(y+2)=6y+4

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Solution for 12-3(y+2)=6y+4 equation: 



12-3(y+2)=6y+4

We move all terms to the left:

12-3(y+2)-(6y+4)=0

We multiply parentheses

-3y-(6y+4)-6+12=0

We get rid of parentheses

-3y-6y-4-6+12=0

We add all the numbers together, and all the variables

-9y+2=0

We move all terms containing y to the left, all other terms to the right

-9y=-2

y=-2/-9

y=2/9

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