12-3(y+1)=1-3(y-2)

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Solution for 12-3(y+1)=1-3(y-2) equation: 


Simplifying
12 + -3(y + 1) = 1 + -3(y + -2)

Reorder the terms:
12 + -3(1 + y) = 1 + -3(y + -2)
12 + (1 * -3 + y * -3) = 1 + -3(y + -2)
12 + (-3 + -3y) = 1 + -3(y + -2)

Combine like terms: 12 + -3 = 9
9 + -3y = 1 + -3(y + -2)

Reorder the terms:
9 + -3y = 1 + -3(-2 + y)
9 + -3y = 1 + (-2 * -3 + y * -3)
9 + -3y = 1 + (6 + -3y)

Combine like terms: 1 + 6 = 7
9 + -3y = 7 + -3y

Add '3y' to each side of the equation.
9 + -3y + 3y = 7 + -3y + 3y

Combine like terms: -3y + 3y = 0
9 + 0 = 7 + -3y + 3y
9 = 7 + -3y + 3y

Combine like terms: -3y + 3y = 0
9 = 7 + 0
9 = 7

Solving
9 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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