12-2z=2(z-4)

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Solution for 12-2z=2(z-4) equation: 



12-2z=2(z-4)

We move all terms to the left:

12-2z-(2(z-4))=0



We calculate terms in parentheses: -(2(z-4)), so:

2(z-4)

We multiply parentheses

2z-8

Back to the equation:

-(2z-8)



We get rid of parentheses

-2z-2z+8+12=0

We add all the numbers together, and all the variables

-4z+20=0

We move all terms containing z to the left, all other terms to the right

-4z=-20

z=-20/-4

z=+5

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