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12-2x=4x+4(3+4x)
We move all terms to the left:
12-2x-(4x+4(3+4x))=0
We add all the numbers together, and all the variables
-2x-(4x+4(4x+3))+12=0
We calculate terms in parentheses: -(4x+4(4x+3)), so:We get rid of parentheses
4x+4(4x+3)
We multiply parentheses
4x+16x+12
We add all the numbers together, and all the variables
20x+12
Back to the equation:
-(20x+12)
-2x-20x-12+12=0
We add all the numbers together, and all the variables
-22x=0
x=0/-22
x=0
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