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12-2/3x=x-7
We move all terms to the left:
12-2/3x-(x-7)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
-2/3x-x+7+12=0
We multiply all the terms by the denominator
-x*3x+7*3x+12*3x-2=0
Wy multiply elements
-3x^2+21x+36x-2=0
We add all the numbers together, and all the variables
-3x^2+57x-2=0
a = -3; b = 57; c = -2;
Δ = b2-4ac
Δ = 572-4·(-3)·(-2)
Δ = 3225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3225}=\sqrt{25*129}=\sqrt{25}*\sqrt{129}=5\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-5\sqrt{129}}{2*-3}=\frac{-57-5\sqrt{129}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+5\sqrt{129}}{2*-3}=\frac{-57+5\sqrt{129}}{-6} $
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