12-2(3n-6)=20

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Solution for 12-2(3n-6)=20 equation: 



12-2(3n-6)=20

We move all terms to the left:

12-2(3n-6)-(20)=0

We add all the numbers together, and all the variables

-2(3n-6)-8=0

We multiply parentheses

-6n+12-8=0

We add all the numbers together, and all the variables

-6n+4=0

We move all terms containing n to the left, all other terms to the right

-6n=-4

n=-4/-6

n=2/3

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