12-10(n+10)=7-11(n+8)

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Solution for 12-10(n+10)=7-11(n+8) equation: 



12-10(n+10)=7-11(n+8)

We move all terms to the left:

12-10(n+10)-(7-11(n+8))=0

We multiply parentheses

-10n-(7-11(n+8))-100+12=0



We calculate terms in parentheses: -(7-11(n+8)), so:

7-11(n+8)

determiningTheFunctionDomain
-11(n+8)+7

We multiply parentheses

-11n-88+7

We add all the numbers together, and all the variables

-11n-81

Back to the equation:

-(-11n-81)



We add all the numbers together, and all the variables

-10n-(-11n-81)-88=0

We get rid of parentheses

-10n+11n+81-88=0

We add all the numbers together, and all the variables

n-7=0

We move all terms containing n to the left, all other terms to the right

n=7

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