12-1/6(12z+54)=-3z-9

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Solution for 12-1/6(12z+54)=-3z-9 equation: 



12-1/6(12z+54)=-3z-9

We move all terms to the left:

12-1/6(12z+54)-(-3z-9)=0



Domain of the equation: 6(12z+54)!=0

z∈R



We get rid of parentheses

-1/6(12z+54)+3z+9+12=0

We multiply all the terms by the denominator


3z*6(12z+54)+9*6(12z+54)+12*6(12z+54)-1=0

Wy multiply elements

18z^2(1+54z(1+72z(1-1=0

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