12-(x-4)=8+(x+4)

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Solution for 12-(x-4)=8+(x+4) equation: 



12-(x-4)=8+(x+4)

We move all terms to the left:

12-(x-4)-(8+(x+4))=0

We get rid of parentheses

-x-(8+(x+4))+4+12=0



We calculate terms in parentheses: -(8+(x+4)), so:

8+(x+4)

determiningTheFunctionDomain
(x+4)+8

We get rid of parentheses

x+4+8

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We add all the numbers together, and all the variables

-1x-(x+12)+16=0

We get rid of parentheses

-1x-x-12+16=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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