12-(4+n)=28

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Solution for 12-(4+n)=28 equation: 



12-(4+n)=28

We move all terms to the left:

12-(4+n)-(28)=0

We add all the numbers together, and all the variables

-(n+4)+12-28=0

We add all the numbers together, and all the variables

-(n+4)-16=0

We get rid of parentheses

-n-4-16=0

We add all the numbers together, and all the variables

-1n-20=0

We move all terms containing n to the left, all other terms to the right

-n=20

n=20/-1

n=-20

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