12-(3x-100)=7x-(20-2x)

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Solution for 12-(3x-100)=7x-(20-2x) equation: 



12-(3x-100)=7x-(20-2x)

We move all terms to the left:

12-(3x-100)-(7x-(20-2x))=0

We add all the numbers together, and all the variables

-(3x-100)-(7x-(-2x+20))+12=0

We get rid of parentheses

-3x-(7x-(-2x+20))+100+12=0



We calculate terms in parentheses: -(7x-(-2x+20)), so:

7x-(-2x+20)

We get rid of parentheses

7x+2x-20

We add all the numbers together, and all the variables

9x-20

Back to the equation:

-(9x-20)



We add all the numbers together, and all the variables

-3x-(9x-20)+112=0

We get rid of parentheses

-3x-9x+20+112=0

We add all the numbers together, and all the variables

-12x+132=0

We move all terms containing x to the left, all other terms to the right

-12x=-132

x=-132/-12

x=+11

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