12-(3r+2)=7(r+6)

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Solution for 12-(3r+2)=7(r+6) equation: 



12-(3r+2)=7(r+6)

We move all terms to the left:

12-(3r+2)-(7(r+6))=0

We get rid of parentheses

-3r-(7(r+6))-2+12=0



We calculate terms in parentheses: -(7(r+6)), so:

7(r+6)

We multiply parentheses

7r+42

Back to the equation:

-(7r+42)



We add all the numbers together, and all the variables

-3r-(7r+42)+10=0

We get rid of parentheses

-3r-7r-42+10=0

We add all the numbers together, and all the variables

-10r-32=0

We move all terms containing r to the left, all other terms to the right

-10r=32

r=32/-10

r=-3+1/5

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