12-(2-4y)=7+y-(5-4y)

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Solution for 12-(2-4y)=7+y-(5-4y) equation: 



12-(2-4y)=7+y-(5-4y)

We move all terms to the left:

12-(2-4y)-(7+y-(5-4y))=0

We add all the numbers together, and all the variables

-(-4y+2)-(7+y-(-4y+5))+12=0

We get rid of parentheses

4y-(7+y-(-4y+5))-2+12=0



We calculate terms in parentheses: -(7+y-(-4y+5)), so:

7+y-(-4y+5)

determiningTheFunctionDomain
y-(-4y+5)+7

We get rid of parentheses

y+4y-5+7

We add all the numbers together, and all the variables

5y+2

Back to the equation:

-(5y+2)



We add all the numbers together, and all the variables

4y-(5y+2)+10=0

We get rid of parentheses

4y-5y-2+10=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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