12+8(x-5)=4(x+3)+4x

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Solution for 12+8(x-5)=4(x+3)+4x equation: 


Simplifying
12 + 8(x + -5) = 4(x + 3) + 4x

Reorder the terms:
12 + 8(-5 + x) = 4(x + 3) + 4x
12 + (-5 * 8 + x * 8) = 4(x + 3) + 4x
12 + (-40 + 8x) = 4(x + 3) + 4x

Combine like terms: 12 + -40 = -28
-28 + 8x = 4(x + 3) + 4x

Reorder the terms:
-28 + 8x = 4(3 + x) + 4x
-28 + 8x = (3 * 4 + x * 4) + 4x
-28 + 8x = (12 + 4x) + 4x

Combine like terms: 4x + 4x = 8x
-28 + 8x = 12 + 8x

Add '-8x' to each side of the equation.
-28 + 8x + -8x = 12 + 8x + -8x

Combine like terms: 8x + -8x = 0
-28 + 0 = 12 + 8x + -8x
-28 = 12 + 8x + -8x

Combine like terms: 8x + -8x = 0
-28 = 12 + 0
-28 = 12

Solving
-28 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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