12+5z=7(z-1)

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Solution for 12+5z=7(z-1) equation: 



12+5z=7(z-1)

We move all terms to the left:

12+5z-(7(z-1))=0



We calculate terms in parentheses: -(7(z-1)), so:

7(z-1)

We multiply parentheses

7z-7

Back to the equation:

-(7z-7)



We get rid of parentheses

5z-7z+7+12=0

We add all the numbers together, and all the variables

-2z+19=0

We move all terms containing z to the left, all other terms to the right

-2z=-19

z=-19/-2

z=9+1/2

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