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12+5a=23(a)2
We move all terms to the left:
12+5a-(23(a)2)=0
determiningTheFunctionDomain 5a-23a2+12=0
We add all the numbers together, and all the variables
-23a^2+5a+12=0
a = -23; b = 5; c = +12;
Δ = b2-4ac
Δ = 52-4·(-23)·12
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1129}}{2*-23}=\frac{-5-\sqrt{1129}}{-46} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1129}}{2*-23}=\frac{-5+\sqrt{1129}}{-46} $
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