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12+5/3b+11-18=2011
We move all terms to the left:
12+5/3b+11-18-(2011)=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
5/3b-2006=0
We multiply all the terms by the denominator
-2006*3b+5=0
Wy multiply elements
-6018b+5=0
We move all terms containing b to the left, all other terms to the right
-6018b=-5
b=-5/-6018
b=5/6018
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