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12+4-6x=3(2x+4/3
We move all terms to the left:
12+4-6x-(3(2x+4/3)=0
We add all the numbers together, and all the variables
-6x-(3(+2x+4/3)+12+4=0
We multiply all the terms by the denominator
-6x*3)+12+4-(3(+2x+4=0
Wy multiply elements
-18x^2=0
a = -18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-18)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-36}=0$
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