12+4(-12j-11)=-4(13j-3)

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Solution for 12+4(-12j-11)=-4(13j-3) equation: 



12+4(-12j-11)=-4(13j-3)

We move all terms to the left:

12+4(-12j-11)-(-4(13j-3))=0

We multiply parentheses

-48j-(-4(13j-3))-44+12=0



We calculate terms in parentheses: -(-4(13j-3)), so:

-4(13j-3)

We multiply parentheses

-52j+12

Back to the equation:

-(-52j+12)



We add all the numbers together, and all the variables

-48j-(-52j+12)-32=0

We get rid of parentheses

-48j+52j-12-32=0

We add all the numbers together, and all the variables

4j-44=0

We move all terms containing j to the left, all other terms to the right

4j=44

j=44/4

j=11

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