12+3x=40+11x

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Solution for 12+3x=40+11x equation: 



12+3x=40+11x

We move all terms to the left:

12+3x-(40+11x)=0

We add all the numbers together, and all the variables

3x-(11x+40)+12=0

We get rid of parentheses

3x-11x-40+12=0

We add all the numbers together, and all the variables

-8x-28=0

We move all terms containing x to the left, all other terms to the right

-8x=28

x=28/-8

x=-3+1/2

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