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12+2x+2-(x-3)=10x-(2-x+7x+1
We move all terms to the left:
12+2x+2-(x-3)-(10x-(2-x+7x+1)=0
We add all the numbers together, and all the variables
2x-(x-3)-(10x-(6x+3)+12+2=0
We get rid of parentheses
2x-x-(10x-(6x+3)+12+2+3=0
We add all the numbers together, and all the variables
x-(10x-(6x+3)+12+2+3=0
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