12+2(x+4)=6-(x-4)

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Solution for 12+2(x+4)=6-(x-4) equation: 



12+2(x+4)=6-(x-4)

We move all terms to the left:

12+2(x+4)-(6-(x-4))=0

We multiply parentheses

2x-(6-(x-4))+8+12=0



We calculate terms in parentheses: -(6-(x-4)), so:

6-(x-4)

determiningTheFunctionDomain
-(x-4)+6

We get rid of parentheses

-x+4+6

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

2x-(-1x+10)+20=0

We get rid of parentheses

2x+1x-10+20=0

We add all the numbers together, and all the variables

3x+10=0

We move all terms containing x to the left, all other terms to the right

3x=-10

x=-10/3

x=-3+1/3

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