12+1/6x=17-2/3x

Solution for 12+1/6x=17-2/3x equation:

12+1/6x=17-2/3x

We move all terms to the left:

12+1/6x-(17-2/3x)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/6x-(-2/3x+17)+12=0

We get rid of parentheses

1/6x+2/3x-17+12=0

We calculate fractions


3x/18x^2+12x/18x^2-17+12=0

We add all the numbers together, and all the variables

3x/18x^2+12x/18x^2-5=0

We multiply all the terms by the denominator


3x+12x-5*18x^2=0

We add all the numbers together, and all the variables

15x-5*18x^2=0

Wy multiply elements

-90x^2+15x=0

a = -90; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-90)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-90}=\frac{-30}{-180}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-90}=\frac{0}{-180}
=0
$