12+1/5(10x+5)=57

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Solution for 12+1/5(10x+5)=57 equation: 



12+1/5(10x+5)=57

We move all terms to the left:

12+1/5(10x+5)-(57)=0



Domain of the equation: 5(10x+5)!=0

x∈R



We add all the numbers together, and all the variables

1/5(10x+5)-45=0

We multiply all the terms by the denominator


-45*5(10x+5)+1=0

Wy multiply elements

-225x(1+1=0

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